-5t^2+10=t+40

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Solution for -5t^2+10=t+40 equation: 



-5t^2+10=t+40

We move all terms to the left:

-5t^2+10-(t+40)=0

We get rid of parentheses

-5t^2-t-40+10=0

We add all the numbers together, and all the variables

-5t^2-1t-30=0

a = -5; b = -1; c = -30;
Δ = b2-4ac
Δ = -12-4·(-5)·(-30)
Δ = -599
Delta is less than zero, so there is no solution for the equation

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